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QUANTITATIVE APTITUDE TEST PAPER 4
QUANTITATIVE APTITUDE TEST PAPER 4 : EXPLANATORY ANSWERS
1. Required distance = sqrt (3-3) 2 + (3 (- 4) 2
)
= sqrt (7) 2
= 7 Units.
Hence[1]
2. The required point is
[ 2 * 8 + 1 * 5 / 2 + 1 , 2 * 5 + 1 * (- 3 ) / (2 + 1) ]
= 21 / 3, 15 / 3
= ( 7 , 5)
Hence[2]
3. A is the midpoint of yz,
The coordinates of A are [ 2+4 / 2 , - 2 + 4 / 2 , -2 + 2 / 2 ]
= ( 3 , 0)
XA = sqrt (6 3) 2 + ( - 2 0 ) 2
=sqrt 3 2 + 2 2
= sqrt 9 + 4 = sqrt 13 Units
Hence[3]
4. Let the ratio be K : 1
TK + 1 * ( - 4 ) / K + 1 = 0
TK = 4
K = 4 / 7
The ratio is 4/7 : 1
= 4 : 7
Hence [4]
5. b + b + 2 / 2 = 2
2b + 2 = 4
2b = 2
b = 1
Hence[1]
6. Slope = y 2 - y1 / x2 - x1
= 3 - 6 / 5 + 4 = -3 / 9 = -1/3
Hence[2]
7. Putting y = 5 in x 2 + y 2 = 34
= x 2 + 25 = 34
x 2 = a \ x = ± 3
points are ( 3 , 5 ) and ( 3, -5)
Hence[3]
8. The series is 52, 53, 62 and so on
9. Value of Machinery after 2 years = 60000 ( 1 15 / 100) 2
60000 ( 115 / 100) 2
= Rs 43350
Hence[1]
10. 8 0 / 100 P = 40 / 100 Q = 40 / 100 * X/100
8 / 10 = 4 x / 1000
X = 8000 / 40 = 200
Hence[2]
11. Population 2 years ago = 16093 / (1 + 10 / 100 ) 2
= 16093 * 10000 / 12100
= 13300
Hence[1]
12. A:C = 2/3 * 3/4
=1:2
Hence[4]
13. Let the fraction be x/y
New fraction = 115% of x / 110% of y = 23x / 22y = 15 / 26
x / y = ( 15/26 * 22 / 23 ) = 330 / 598 = 165 / 299
Hence[4]
14. When y = 10, X = 20, Z = 5
x = k, and z = k 2 / y 5 = k 2 / 10
K 2 = 50
X = 2y and Z = 50 / y
When y = 20
Z = 50 / 20 = 2.5
Hence[1]
15. For a perfect division into whole numbers the sum of the terms of the ratio must
divide 10 Therefore the ratio cannot be 3 : 4
Hence[4]
16. SP = 10 , Q = 15 , R = x
P = x / 5, Q = x / 10 and R = x / 15
P : Q : R = x /5 : x / 10 : x / 15
= 6 : 3 : 2
Hence[1]
17. S.P at 50% discount = Rs 250
S.P. after 2 successive discounts of 5 % and 5% = 95% of ( 55% of 500) =
[ 95 / 100 * 55 / 100 * 500 ]
= Rs. 261.25
differences = Rs 11.25
Hence[2]
18. Rate unstream = 10 / 4 = 2.5 kmph
Rate downstream = 20 / 4 = 5 kmph
velocity of current = 1 / 2 ( 5 - 2.5 ) kmph
= 1.25 kmph
Hence[2]
19. Rate upstream = 50 / 10 = 5 kmph
Rate downstream = 40 / 9 = 4.44 kmph
Rate in still water = 1 / 2 ( 5 * 4.44)
= 4.72 kmph
Hence[4]
20. Rate upstream = 1
rate downstream = 7
Total time take = [ 14 / 1 + 14 / 7]
= 14 + 2 = 16 hours
Hence[1]
21. A cone is generated with radius 10 cm & vertical height = 6 cm
Volume = 1 P / 3 * 100 * 6 = 200 P
Hence [ 1 ]
22. Let him have Rs. X when he intered the Amount spent = 2 + x / 5
x 2 x / 5 = 0
5x - 10 x = 0
4x = 10 , x = 2.5
When I entered the 3rd shop, I had 2.5 ( 2.5 + 2 ) = 11.25
When I entered the 2nd shop I had 11.25 + 2 ( 2.5) = 33.125
When I entered the 1st shop I had 33.125 + 2 (2.5) = 87.8125
Hence [1]
23. Total time = 5 / 1 + 4 / 2 + 12 / 6
= 9 hours
Total distance = 21 km
Average speed = 21 / 9 = 2.33 every hr.
Hence[1]
24. It cannot be determined as it depends on the position of the path. Hence[4]
25. ( p - q ) 2 = ( x y ) 2
p - q = ± x y
p q = x - y or y x
x = p - q + y or q - p + y
Hence [3]
26. Let the sum interested at 6% be x
X * 7 * 6 / 100 = 100
= ( 13400 x ) * 7 * 4 / 100
42 x / 10 = 93800 7x / 25
42 x = 93800 * 4 - 28 x
70 x = 93800 * 4 / 70 = Rs 5360
Hence[1]
27. Let d be the distance and t be the normal time
D / 6 = t 10 / 60
D / 5 = t + 10 / 60
D / 6 - d / 5 = - 10 / 60 - 10 / 60
5d 6d / 30 = -20 / 60
-2d = -20
d = 10 km
Hence [ 1 ]
28. Each number in the series in the precious numbers added to the sum
of its digits.
the last no. = 1 + 4 + 7 + 147
= 159
Hence [ 3 ]
29. Both the digits must be even and odd multiples of 6 will not be
divisibleby 12
The number is 42
And its reverse is 24
The difference = 18
Hence [ 1 ]
30. Let there be x tractors
Area of farm = 2x 2
When one tractor is stolen x 1 will
Remain 2x 2 - 2(x 1) 2 = 62
Solving
2x 2 - 2 (x 2 - 2x + 1) = 62
2x 2 - 2x 2 + 4x - 2 = 62
4x = 60
x = 15
No. of tractors = 15 - 1 = 14
Hence [ 1 ]
31. All seven digits with have to be used to make a number greater than
a million.
Since there are 3 6s and 2 7s the number of distinct persutations = 7! / 2! 3!
But all persutations starting with zero should let be counted
7! / 2! 3! - 5! / 2! 3!
= 410
Hence [1]
32. Let the speed of the burglar and the guard be x min /sec
and y min / sec
The guard covered the distance in 3min 10 sec for which the thief took 5 minutes
Therefore 300 x = 190 Y
30x = 19y
Also given that
356 * x = 3560 m
x = 10 m / sec
and y = 300 * 10 / 190 = 15.07 m / sec
Hence [ 1 ]
33. Let profit be Rs p
Then x gets 0.25 p. and y gets 0.75 p. in the ratio of their investement.
Y pay Rs. 10, 000 per month for 8 months
= 10000 * 8 = Rs 80, 000
= 0.25 p + 80000 = 0.75 p - 80000
0. 5 p = 160000
P = 320, 000
Hence [2]
34. The series is 3*1+1, 4*3+1 and so on
35. For any positions of A B & C there are 2 ways of completing the
queue either D willl be
ahead or behind E since of the total combinations of forming a queue half will have D
ahead
of E.
Total No. of ways = 5! = 120
But in this case = 60
Hence[ 1 ]
36. One task = 5 men 10 hrs 1 day = 50 - man hours
same task = 4 women 8 hrs 2 days = 64 - women hours
same tassk = 5 boys 5 hrs 4 days = 100 - boy hours
each day total labour available = 20 men = (200 man hours) + 9 women (72 women hours ) +
10 boys = 50 boy hours
200 * 100 / 50 + 72 * 100 / 64 + 50
= 400 + 150 + 50
= 600 boy hours
boy hours task days
100 1
1
600 1000
?
= 1000 * 100 / 600 = 167 days
from 1st march 167 days = 14 th August.
Hence [ 4 ]
37. Let ys salary be x
xs salary = 150 x
zs salary = 75 x / 100
x + 75 x / 100 + 150x / 100 = 325 x / 100
325x / 100 = 3, 25, 000
x = 325000 * 100 / 325 = 1, 00, 000.
[ Hence ]
38. Distance Time Speed Days
x 24 - 18 = 6 hrs y 200
2x 24 - 9 = 15 hrs 2y ?
Days = 200 * 2x / x * 6 / 15 * y / 2y = 80 days.
Hence [ 1 ]
39. In 1 minute, tyre flat = 1 / 10 -------- Puncture (I)
In 1 minute, tyre flat = 1 / 5 -------- puncture (II)
Together 1 / 10 + 1 / 5 = 3 / 10 in one minute
Remaining = 7 / 10
= 7 / 10 * 10 / 3 = 7 / 3
= 2 1/ 3 minutes
Hence[1]
40. ( 1 ) ( 1 ) / 20 4 = 1 / 16
Hence [1]
41. Two numbers whose sum is 11 and product of their squares is 30 are
sqrt 5 & sqrt 6
sqrt 11 + 2 sqrt 30
= sqrt ( sqrt 5 + sqrt 6 ) 2
= ( sqrt5 + sqrt 6 )
Hence [ 1 ]
42. 17164 - 3 = 17161
sqrt 17161 = 131
No. of men in the last row was 131
Hence [ 2 ]
43. Let the term be x : x + 50
X / x + 50 = 3 / 5
5x = 3x + 150 = 2x = 150
x = 75
Hence [4]
44. The ratio of coins = 3/1 : 2/2 : 4/4
= 3 : 1 : 1
The amount of 25 paise coins is Rs. 60
No of coins = 60 / 0.25
= 240 coins
Hence [1]
45. J + A + V = 11250
J = ¼ ( A + V )
4 J = A + V
5 J = 11250
J = 11250 / 5 = 2250
Hence [ 3 ]
46. Let x invest Rs a for 12 months Y invest Rs 4a for 4 months Z invest Rs 3a for 2 months
The ratio is 12a : 16a : 6a
Zs share = Rs 8500 * 3 / 17 = Rs 1500
Hence [ 4 ]
47. S. P of 75 toys = C P of 75 toys
Let CP of each toy = Rs 1
CP of 50 toys = Rs 50
SP of 50 toys = Rs 75
= 25 * 100 / 50
= 50%
Hence [ 3 ]
48.Let Qs contribution = Rs x
8000 * 6 : 3x
16000 : x
ratio of profit ½ : ½
= 1 : 1
16000 / x = 1 / 1
= Rs 16000
Hence [ 4 ]
49. Let the marked price be Rs. 100
Final SP after 2 discounts = 15%, 75% of Rs 100
= Rs. 63.75
Single discount = 100 - 63.75 = 36.25 %
Hence [ 3 ]
50. Let C.P. of 1 car=x
C.P. of 4 cars=4x
% profit=2x/4x*100
=50%
Hence[1]